Base | Representation |
---|---|
bin | 11101000111110111011… |
… | …100000110010110001111 |
3 | 21002022201210222012121100 |
4 | 131013313130012112033 |
5 | 230242141122143043 |
6 | 4131220055034143 |
7 | 264406232635341 |
oct | 35076734062617 |
9 | 7068653865540 |
10 | 2001311131023 |
11 | 701829a60a46 |
12 | 283a4b06b953 |
13 | 116952098949 |
14 | 6cc14a6b291 |
15 | 370d316acd3 |
hex | 1d1f770658f |
2001311131023 has 12 divisors (see below), whose sum is σ = 2900997528520. Its totient is φ = 1329492905136.
The previous prime is 2001311130979. The next prime is 2001311131031. The reversal of 2001311131023 is 3201311131002.
2001311131023 is a `hidden beast` number, since 20 + 0 + 1 + 311 + 1 + 310 + 23 = 666.
It is not a de Polignac number, because 2001311131023 - 210 = 2001311129999 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2001311130987 and 2001311131005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001311131033) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 392873608 + ... + 392878701.
Almost surely, 22001311131023 is an apocalyptic number.
2001311131023 is a deficient number, since it is larger than the sum of its proper divisors (899686397497).
2001311131023 is a wasteful number, since it uses less digits than its factorization.
2001311131023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 785752598 (or 785752595 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 2001311131023 its reverse (3201311131002), we get a palindrome (5202622262025).
The spelling of 2001311131023 in words is "two trillion, one billion, three hundred eleven million, one hundred thirty-one thousand, twenty-three".
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