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2001311131031 is a prime number
BaseRepresentation
bin11101000111110111011…
…100000110010110010111
321002022201210222012121122
4131013313130012112113
5230242141122143111
64131220055034155
7264406232635352
oct35076734062627
97068653865548
102001311131031
11701829a60a53
12283a4b06b95b
13116952098954
146cc14a6b299
15370d316acdb
hex1d1f7706597

2001311131031 has 2 divisors, whose sum is σ = 2001311131032. Its totient is φ = 2001311131030.

The previous prime is 2001311130979. The next prime is 2001311131033. The reversal of 2001311131031 is 1301311131002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2001311131031 - 26 = 2001311130967 is a prime.

It is a super-2 number, since 2×20013111310312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 2001311131033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2001311131033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000655565515 + 1000655565516.

It is an arithmetic number, because the mean of its divisors is an integer number (1000655565516).

Almost surely, 22001311131031 is an apocalyptic number.

2001311131031 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001311131031 is an equidigital number, since it uses as much as digits as its factorization.

2001311131031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 2001311131031 its reverse (1301311131002), we get a palindrome (3302622262033).

The spelling of 2001311131031 in words is "two trillion, one billion, three hundred eleven million, one hundred thirty-one thousand, thirty-one".