Base | Representation |
---|---|
bin | 11101000111110111011… |
… | …111001111001101010011 |
3 | 21002022201212112000011121 |
4 | 131013313133033031103 |
5 | 230242141330004442 |
6 | 4131220124423111 |
7 | 264406242633061 |
oct | 35076737171523 |
9 | 7068655460147 |
10 | 2001311953747 |
11 | 70182a473087 |
12 | 283a4b3a7a97 |
13 | 1169522c6272 |
14 | 6cc14c03031 |
15 | 370d327e967 |
hex | 1d1f77cf353 |
2001311953747 has 2 divisors, whose sum is σ = 2001311953748. Its totient is φ = 2001311953746.
The previous prime is 2001311953727. The next prime is 2001311953763. The reversal of 2001311953747 is 7473591131002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001311953747 - 223 = 2001303565139 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001311953717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000655976873 + 1000655976874.
It is an arithmetic number, because the mean of its divisors is an integer number (1000655976874).
Almost surely, 22001311953747 is an apocalyptic number.
2001311953747 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001311953747 is an equidigital number, since it uses as much as digits as its factorization.
2001311953747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 158760, while the sum is 43.
The spelling of 2001311953747 in words is "two trillion, one billion, three hundred eleven million, nine hundred fifty-three thousand, seven hundred forty-seven".
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