Base | Representation |
---|---|
bin | 11101000111110111100… |
… | …000001011010111100001 |
3 | 21002022201212222112012001 |
4 | 131013313200023113201 |
5 | 230242141410401121 |
6 | 4131220134004001 |
7 | 264406245010351 |
oct | 35076740132741 |
9 | 7068655875161 |
10 | 2001312200161 |
11 | 70182a62122a |
12 | 283a4b4a6601 |
13 | 116952381481 |
14 | 6cc14c68b61 |
15 | 370d32cc991 |
hex | 1d1f780b5e1 |
2001312200161 has 2 divisors, whose sum is σ = 2001312200162. Its totient is φ = 2001312200160.
The previous prime is 2001312200119. The next prime is 2001312200231. The reversal of 2001312200161 is 1610022131002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1998561827025 + 2750373136 = 1413705^2 + 52444^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001312200161 - 231 = 1999164716513 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001312200101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000656100080 + 1000656100081.
It is an arithmetic number, because the mean of its divisors is an integer number (1000656100081).
Almost surely, 22001312200161 is an apocalyptic number.
It is an amenable number.
2001312200161 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001312200161 is an equidigital number, since it uses as much as digits as its factorization.
2001312200161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2001312200161 its reverse (1610022131002), we get a palindrome (3611334331163).
The spelling of 2001312200161 in words is "two trillion, one billion, three hundred twelve million, two hundred thousand, one hundred sixty-one".
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