Base | Representation |
---|---|
bin | 11101000111111000000… |
… | …010001011011000101011 |
3 | 21002022202111202100111001 |
4 | 131013320002023120223 |
5 | 230242201201110011 |
6 | 4131221053015431 |
7 | 264406413531604 |
oct | 35077002133053 |
9 | 7068674670431 |
10 | 2001321113131 |
11 | 70183465971a |
12 | 283a52484577 |
13 | 116954182312 |
14 | 6cc16108dab |
15 | 370d3e8d7c1 |
hex | 1d1f808b62b |
2001321113131 has 2 divisors, whose sum is σ = 2001321113132. Its totient is φ = 2001321113130.
The previous prime is 2001321113111. The next prime is 2001321113177. The reversal of 2001321113131 is 1313111231002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001321113131 - 29 = 2001321112619 is a prime.
It is a super-2 number, since 2×20013211131312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001321113099 and 2001321113108.
It is not a weakly prime, because it can be changed into another prime (2001321113111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000660556565 + 1000660556566.
It is an arithmetic number, because the mean of its divisors is an integer number (1000660556566).
Almost surely, 22001321113131 is an apocalyptic number.
2001321113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001321113131 is an equidigital number, since it uses as much as digits as its factorization.
2001321113131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 2001321113131 its reverse (1313111231002), we get a palindrome (3314432344133).
The spelling of 2001321113131 in words is "two trillion, one billion, three hundred twenty-one million, one hundred thirteen thousand, one hundred thirty-one".
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