Base | Representation |
---|---|
bin | 11101000111111000111… |
… | …000011011100010001111 |
3 | 21002022210111111220021222 |
4 | 131013320320123202033 |
5 | 230242213321210210 |
6 | 4131222321513555 |
7 | 264406645444130 |
oct | 35077070334217 |
9 | 7068714456258 |
10 | 2001335335055 |
11 | 701841692881 |
12 | 283a571a28bb |
13 | 1169570c1764 |
14 | 6cc17d6bc87 |
15 | 370d534c655 |
hex | 1d1f8e1b88f |
2001335335055 has 64 divisors (see below), whose sum is σ = 2918315243520. Its totient is φ = 1287979646976.
The previous prime is 2001335335003. The next prime is 2001335335057. The reversal of 2001335335055 is 5505335331002.
It is a cyclic number.
It is not a de Polignac number, because 2001335335055 - 216 = 2001335269519 is a prime.
It is a super-2 number, since 2×20013353350552 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001335335057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11253416 + ... + 11429874.
It is an arithmetic number, because the mean of its divisors is an integer number (45598675680).
Almost surely, 22001335335055 is an apocalyptic number.
2001335335055 is a deficient number, since it is larger than the sum of its proper divisors (916979908465).
2001335335055 is a wasteful number, since it uses less digits than its factorization.
2001335335055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 176760.
The product of its (nonzero) digits is 101250, while the sum is 35.
The spelling of 2001335335055 in words is "two trillion, one billion, three hundred thirty-five million, three hundred thirty-five thousand, fifty-five".
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