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2001403480001 is a prime number
BaseRepresentation
bin11101000111111100111…
…100011000011111000001
321002022222020202000120212
4131013330330120133001
5230242333242330001
64131233154243505
7264411433613342
oct35077474303701
97068866660525
102001403480001
117018770a7112
12283a75b86595
13116968260b03
146cc2302a0c9
15370db30d7bb
hex1d1fcf187c1

2001403480001 has 2 divisors, whose sum is σ = 2001403480002. Its totient is φ = 2001403480000.

The previous prime is 2001403479947. The next prime is 2001403480009. The reversal of 2001403480001 is 1000843041002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1421338455601 + 580065024400 = 1192199^2 + 761620^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001403480001 - 214 = 2001403463617 is a prime.

It is a super-5 number, since 5×20014034800015 (a number of 63 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (2001403480009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000701740000 + 1000701740001.

It is an arithmetic number, because the mean of its divisors is an integer number (1000701740001).

Almost surely, 22001403480001 is an apocalyptic number.

It is an amenable number.

2001403480001 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001403480001 is an equidigital number, since it uses as much as digits as its factorization.

2001403480001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

The spelling of 2001403480001 in words is "two trillion, one billion, four hundred three million, four hundred eighty thousand, one".