Base | Representation |
---|---|
bin | 1001000110011111000011… |
… | …11000111111001000111111 |
3 | 2121212022202000210120221021 |
4 | 10203033201320333020333 |
5 | 10110402224331204401 |
6 | 110322154004245011 |
7 | 4133652425565604 |
oct | 443174170771077 |
9 | 77768660716837 |
10 | 20014042444351 |
11 | 64169a921634a |
12 | 22b2a323a0767 |
13 | b22415633bc7 |
14 | 4d29832226ab |
15 | 24a927aa02a1 |
hex | 1233e1e3f23f |
20014042444351 has 4 divisors (see below), whose sum is σ = 20115636568632. Its totient is φ = 19912448320072.
The previous prime is 20014042444337. The next prime is 20014042444381. The reversal of 20014042444351 is 15344424041002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20014042444351 - 219 = 20014041920063 is a prime.
It is a super-2 number, since 2×200140424443512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20014042444301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50797061845 + ... + 50797062238.
It is an arithmetic number, because the mean of its divisors is an integer number (5028909142158).
Almost surely, 220014042444351 is an apocalyptic number.
20014042444351 is a deficient number, since it is larger than the sum of its proper divisors (101594124281).
20014042444351 is a wasteful number, since it uses less digits than its factorization.
20014042444351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101594124280.
The product of its (nonzero) digits is 61440, while the sum is 34.
Adding to 20014042444351 its reverse (15344424041002), we get a palindrome (35358466485353).
The spelling of 20014042444351 in words is "twenty trillion, fourteen billion, forty-two million, four hundred forty-four thousand, three hundred fifty-one".
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