Base | Representation |
---|---|
bin | 10010101000111100… |
… | …001111101011100101 |
3 | 1220122211022110002120 |
4 | 102220330033223211 |
5 | 311442120444331 |
6 | 13105554300153 |
7 | 1305654120303 |
oct | 225074175345 |
9 | 56584273076 |
10 | 20014234341 |
11 | 8540571542 |
12 | 3a66887659 |
13 | 1b6c61c91a |
14 | d7c14d273 |
15 | 7c212d796 |
hex | 4a8f0fae5 |
20014234341 has 4 divisors (see below), whose sum is σ = 26685645792. Its totient is φ = 13342822892.
The previous prime is 20014234327. The next prime is 20014234367. The reversal of 20014234341 is 14343241002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20014234341 - 213 = 20014226149 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20014234391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3335705721 + ... + 3335705726.
It is an arithmetic number, because the mean of its divisors is an integer number (6671411448).
Almost surely, 220014234341 is an apocalyptic number.
It is an amenable number.
20014234341 is a deficient number, since it is larger than the sum of its proper divisors (6671411451).
20014234341 is an equidigital number, since it uses as much as digits as its factorization.
20014234341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6671411450.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 20014234341 its reverse (14343241002), we get a palindrome (34357475343).
The spelling of 20014234341 in words is "twenty billion, fourteen million, two hundred thirty-four thousand, three hundred forty-one".
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