Base | Representation |
---|---|
bin | 101101100000011101111110… |
… | …100011101001011001011011 |
3 | 222020122111211222221202221122 |
4 | 231200131332203221121123 |
5 | 202213121441400100443 |
6 | 1545400321545555455 |
7 | 60104606441626052 |
oct | 5540357643513133 |
9 | 866574758852848 |
10 | 200143304300123 |
11 | 58854331609038 |
12 | 1a5451437a5b8b |
13 | 878a5815aa542 |
14 | 375cdb802b399 |
15 | 18212bee12968 |
hex | b6077e8e965b |
200143304300123 has 2 divisors, whose sum is σ = 200143304300124. Its totient is φ = 200143304300122.
The previous prime is 200143304300039. The next prime is 200143304300143. The reversal of 200143304300123 is 321003403341002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200143304300123 - 226 = 200143237191259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200143304300092 and 200143304300101.
It is not a weakly prime, because it can be changed into another prime (200143304300143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100071652150061 + 100071652150062.
It is an arithmetic number, because the mean of its divisors is an integer number (100071652150062).
Almost surely, 2200143304300123 is an apocalyptic number.
200143304300123 is a deficient number, since it is larger than the sum of its proper divisors (1).
200143304300123 is an equidigital number, since it uses as much as digits as its factorization.
200143304300123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 200143304300123 its reverse (321003403341002), we get a palindrome (521146707641125).
The spelling of 200143304300123 in words is "two hundred trillion, one hundred forty-three billion, three hundred four million, three hundred thousand, one hundred twenty-three".
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