200143304300131 has 4 divisors (see below), whose sum is σ = 200554276178032. Its totient is φ = 199732332422232.

The previous prime is 200143304300123. The next prime is 200143304300143. The reversal of 200143304300131 is 131003403341002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200143304300131 - 2³ = 200143304300123 is a prime.

It is a super-2 number, since 2×200143304300131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200143304300096 and 200143304300105.

It is not an unprimeable number, because it can be changed into a prime (200143304330131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205485938220 + ... + 205485939193.

It is an arithmetic number, because the mean of its divisors is an integer number (50138569044508).

Almost surely, 2^{200143304300131} is an apocalyptic number.

200143304300131 is a deficient number, since it is larger than the sum of its proper divisors (410971877901).

200143304300131 is an equidigital number, since it uses as much as digits as its factorization.

200143304300131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 410971877900.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 200143304300131 its reverse (131003403341002), we get a palindrome (331146707641133).

The spelling of 200143304300131 in words is "two hundred trillion, one hundred forty-three billion, three hundred four million, three hundred thousand, one hundred thirty-one".