Base | Representation |
---|---|
bin | 101101100000011110000000… |
… | …111000001010100001110110 |
3 | 222020122111221201012210000022 |
4 | 231200132000320022201312 |
5 | 202213122031331430032 |
6 | 1545400325500245142 |
7 | 60104610423561311 |
oct | 5540360070124166 |
9 | 866574851183008 |
10 | 200143343233142 |
11 | 5885435158aa91 |
12 | 1a5451548407b2 |
13 | 878a58968c52a |
14 | 375cdbd283978 |
15 | 18212c3553512 |
hex | b60780e0a876 |
200143343233142 has 16 divisors (see below), whose sum is σ = 302614539146160. Its totient is φ = 99274985378208.
The previous prime is 200143343233139. The next prime is 200143343233181. The reversal of 200143343233142 is 241332343341002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 788671328 + ... + 788925059.
It is an arithmetic number, because the mean of its divisors is an integer number (18913408696635).
Almost surely, 2200143343233142 is an apocalyptic number.
200143343233142 is a deficient number, since it is larger than the sum of its proper divisors (102471195913018).
200143343233142 is a wasteful number, since it uses less digits than its factorization.
200143343233142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1577596895.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 200143343233142 its reverse (241332343341002), we get a palindrome (441475686574144).
The spelling of 200143343233142 in words is "two hundred trillion, one hundred forty-three billion, three hundred forty-three million, two hundred thirty-three thousand, one hundred forty-two".
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