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2001669953 is a prime number
BaseRepresentation
bin111011101001111…
…0000111101000001
312011111111100222012
41313103300331001
513044411414303
6530342422305
7100413625313
oct16723607501
95144440865
102001669953
11937988298
1247a431995
1325b9104ba
1414dbb17b3
15baae25d8
hex774f0f41

2001669953 has 2 divisors, whose sum is σ = 2001669954. Its totient is φ = 2001669952.

The previous prime is 2001669937. The next prime is 2001669961. The reversal of 2001669953 is 3599661002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1903402384 + 98267569 = 43628^2 + 9913^2 .

It is a cyclic number.

It is not a de Polignac number, because 2001669953 - 24 = 2001669937 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2001669953.

It is not a weakly prime, because it can be changed into another prime (2001669983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000834976 + 1000834977.

It is an arithmetic number, because the mean of its divisors is an integer number (1000834977).

Almost surely, 22001669953 is an apocalyptic number.

It is an amenable number.

2001669953 is a deficient number, since it is larger than the sum of its proper divisors (1).

2001669953 is an equidigital number, since it uses as much as digits as its factorization.

2001669953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87480, while the sum is 41.

The square root of 2001669953 is about 44740.0262963714. The cubic root of 2001669953 is about 1260.2716204964.

The spelling of 2001669953 in words is "two billion, one million, six hundred sixty-nine thousand, nine hundred fifty-three".