Base | Representation |
---|---|
bin | 1001000110101100000010… |
… | …10011110001101111011001 |
3 | 2121212222201202021022101011 |
4 | 10203112001103301233121 |
5 | 10111011013033340433 |
6 | 110325305334253521 |
7 | 4134320225126026 |
oct | 443260123615731 |
9 | 77788652238334 |
10 | 20021012011993 |
11 | 6419955374703 |
12 | 22b42584b72a1 |
13 | b22c86543125 |
14 | 4d3044ada54d |
15 | 24abd48a73cd |
hex | 1235814f1bd9 |
20021012011993 has 2 divisors, whose sum is σ = 20021012011994. Its totient is φ = 20021012011992.
The previous prime is 20021012011969. The next prime is 20021012012021. The reversal of 20021012011993 is 39911021012002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16328323252224 + 3692688759769 = 4040832^2 + 1921637^2 .
It is a cyclic number.
It is not a de Polignac number, because 20021012011993 - 25 = 20021012011961 is a prime.
It is not a weakly prime, because it can be changed into another prime (20021012011393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010506005996 + 10010506005997.
It is an arithmetic number, because the mean of its divisors is an integer number (10010506005997).
Almost surely, 220021012011993 is an apocalyptic number.
It is an amenable number.
20021012011993 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021012011993 is an equidigital number, since it uses as much as digits as its factorization.
20021012011993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 31.
Adding to 20021012011993 its reverse (39911021012002), we get a palindrome (59932033023995).
The spelling of 20021012011993 in words is "twenty trillion, twenty-one billion, twelve million, eleven thousand, nine hundred ninety-three".
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