Base | Representation |
---|---|
bin | 11101001000100110100… |
… | …101011010010011011011 |
3 | 21002101202221022122201111 |
4 | 131020212211122103123 |
5 | 230300301114214321 |
6 | 4131430352201151 |
7 | 264434646033022 |
oct | 35104645322333 |
9 | 7071687278644 |
10 | 2002102101211 |
11 | 7020a5494613 |
12 | 28402bb391b7 |
13 | 116a49c09744 |
14 | 6cc8bb258b9 |
15 | 3712c80c5e1 |
hex | 1d22695a4db |
2002102101211 has 2 divisors, whose sum is σ = 2002102101212. Its totient is φ = 2002102101210.
The previous prime is 2002102101193. The next prime is 2002102101299. The reversal of 2002102101211 is 1121012012002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002102101211 - 221 = 2002100004059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2002102101191 and 2002102101200.
It is not a weakly prime, because it can be changed into another prime (2002162101211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001051050605 + 1001051050606.
It is an arithmetic number, because the mean of its divisors is an integer number (1001051050606).
Almost surely, 22002102101211 is an apocalyptic number.
2002102101211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002102101211 is an equidigital number, since it uses as much as digits as its factorization.
2002102101211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 2002102101211 its reverse (1121012012002), we get a palindrome (3123114113213).
The spelling of 2002102101211 in words is "two trillion, two billion, one hundred two million, one hundred one thousand, two hundred eleven".
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