Base | Representation |
---|---|
bin | 11101001000100111000… |
… | …011100010101110000111 |
3 | 21002101210111011221211111 |
4 | 131020213003202232013 |
5 | 230300310130000012 |
6 | 4131431233345451 |
7 | 264435103131415 |
oct | 35104703425607 |
9 | 7071714157744 |
10 | 2002110000007 |
11 | 7020a999a047 |
12 | 284032708287 |
13 | 116a4b743aa0 |
14 | 6cc8cbc02b5 |
15 | 3712d36cba7 |
hex | 1d2270e2b87 |
2002110000007 has 48 divisors (see below), whose sum is σ = 2320143265440. Its totient is φ = 1716848437248.
The previous prime is 2002110000001. The next prime is 2002110000017. The reversal of 2002110000007 is 7000000112002.
It is not a de Polignac number, because 2002110000007 - 235 = 1967750261639 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002110000001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 445604253 + ... + 445608745.
It is an arithmetic number, because the mean of its divisors is an integer number (48336318030).
Almost surely, 22002110000007 is an apocalyptic number.
2002110000007 is a deficient number, since it is larger than the sum of its proper divisors (318033265433).
2002110000007 is a wasteful number, since it uses less digits than its factorization.
2002110000007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6052 (or 6035 counting only the distinct ones).
The product of its (nonzero) digits is 28, while the sum is 13.
Adding to 2002110000007 its reverse (7000000112002), we get a palindrome (9002110112009).
The spelling of 2002110000007 in words is "two trillion, two billion, one hundred ten million, seven", and thus it is an aban number.
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