Base | Representation |
---|---|
bin | 101101100001011101000001… |
… | …100010101101011001110011 |
3 | 222020212222120211120210012202 |
4 | 231201131001202231121303 |
5 | 202220224112012332242 |
6 | 1545451355210213415 |
7 | 60112524136620134 |
oct | 5541350142553163 |
9 | 866788524523182 |
10 | 200211000120947 |
11 | 588800100951a2 |
12 | 1a556296a2426b |
13 | 8793a7c54875a |
14 | 376239aa07c8b |
15 | 1822e330c8932 |
hex | b617418ad673 |
200211000120947 has 2 divisors, whose sum is σ = 200211000120948. Its totient is φ = 200211000120946.
The previous prime is 200211000120931. The next prime is 200211000121079. The reversal of 200211000120947 is 749021000112002.
200211000120947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200211000120947 - 24 = 200211000120931 is a prime.
It is not a weakly prime, because it can be changed into another prime (200211000128947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105500060473 + 100105500060474.
It is an arithmetic number, because the mean of its divisors is an integer number (100105500060474).
Almost surely, 2200211000120947 is an apocalyptic number.
200211000120947 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211000120947 is an equidigital number, since it uses as much as digits as its factorization.
200211000120947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
Adding to 200211000120947 its reverse (749021000112002), we get a palindrome (949232000232949).
The spelling of 200211000120947 in words is "two hundred trillion, two hundred eleven billion, one hundred twenty thousand, nine hundred forty-seven".
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