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20021101000113 = 310762371031153
BaseRepresentation
bin1001000110101100001101…
…00111001111010110110001
32121212222221221201101010110
410203112012213033112301
510111011203324000423
6110325322233451533
74134322355405433
oct443260647172661
977788857641113
1020021101000113
1164199a0624804
1222b4282270ba9
13b22c9bacc615
144d3052862653
1524abdc5d4193
hex1235869cf5b1

20021101000113 has 8 divisors (see below), whose sum is σ = 26944285458528. Its totient is φ = 13222658604224.

The previous prime is 20021101000097. The next prime is 20021101000127. The reversal of 20021101000113 is 31100010112002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20021101000113 - 24 = 20021101000097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20021101000913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31185515256 + ... + 31185515897.

It is an arithmetic number, because the mean of its divisors is an integer number (3368035682316).

Almost surely, 220021101000113 is an apocalyptic number.

It is an amenable number.

20021101000113 is a deficient number, since it is larger than the sum of its proper divisors (6923184458415).

20021101000113 is a wasteful number, since it uses less digits than its factorization.

20021101000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62371031263.

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 20021101000113 its reverse (31100010112002), we get a palindrome (51121111112115).

The spelling of 20021101000113 in words is "twenty trillion, twenty-one billion, one hundred one million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 107 321 62371031153 187113093459 6673700333371 20021101000113