Base | Representation |
---|---|
bin | 1001000110101100001101… |
… | …00111001111010110111111 |
3 | 2121212222221221201101010222 |
4 | 10203112012213033112333 |
5 | 10111011203324001002 |
6 | 110325322233451555 |
7 | 4134322355405453 |
oct | 443260647172677 |
9 | 77788857641128 |
10 | 20021101000127 |
11 | 64199a0624817 |
12 | 22b4282270bbb |
13 | b22c9bacc626 |
14 | 4d3052862663 |
15 | 24abdc5d41a2 |
hex | 1235869cf5bf |
20021101000127 has 2 divisors, whose sum is σ = 20021101000128. Its totient is φ = 20021101000126.
The previous prime is 20021101000097. The next prime is 20021101000237. The reversal of 20021101000127 is 72100010112002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021101000127 - 212 = 20021100996031 is a prime.
It is a super-2 number, since 2×200211010001272 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021101000427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010550500063 + 10010550500064.
It is an arithmetic number, because the mean of its divisors is an integer number (10010550500064).
Almost surely, 220021101000127 is an apocalyptic number.
20021101000127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021101000127 is an equidigital number, since it uses as much as digits as its factorization.
20021101000127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 20021101000127 its reverse (72100010112002), we get a palindrome (92121111112129).
The spelling of 20021101000127 in words is "twenty trillion, twenty-one billion, one hundred one million, one hundred twenty-seven", and thus it is an aban number.
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