Base | Representation |
---|---|
bin | 1001000110101100001101… |
… | …00111001111010110100001 |
3 | 2121212222221221201101002212 |
4 | 10203112012213033112201 |
5 | 10111011203324000342 |
6 | 110325322233451505 |
7 | 4134322355405411 |
oct | 443260647172641 |
9 | 77788857641085 |
10 | 20021101000097 |
11 | 64199a062479a |
12 | 22b4282270b95 |
13 | b22c9bacc602 |
14 | 4d3052862641 |
15 | 24abdc5d4182 |
hex | 1235869cf5a1 |
20021101000097 has 2 divisors, whose sum is σ = 20021101000098. Its totient is φ = 20021101000096.
The previous prime is 20021101000093. The next prime is 20021101000127. The reversal of 20021101000097 is 79000010112002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17345900555281 + 2675200444816 = 4164841^2 + 1635604^2 .
It is a cyclic number.
It is not a de Polignac number, because 20021101000097 - 22 = 20021101000093 is a prime.
It is not a weakly prime, because it can be changed into another prime (20021101000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010550500048 + 10010550500049.
It is an arithmetic number, because the mean of its divisors is an integer number (10010550500049).
Almost surely, 220021101000097 is an apocalyptic number.
It is an amenable number.
20021101000097 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021101000097 is an equidigital number, since it uses as much as digits as its factorization.
20021101000097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 20021101000097 its reverse (79000010112002), we get a palindrome (99021111112099).
The spelling of 20021101000097 in words is "twenty trillion, twenty-one billion, one hundred one million, ninety-seven", and thus it is an aban number.
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