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2002110110041 is a prime number
BaseRepresentation
bin11101001000100111000…
…011111101100101011001
321002101210111101112202211
4131020213003331211121
5230300310142010131
64131431235555121
7264435104100256
oct35104703754531
97071714345684
102002110110041
117020a9a64788
1228403275baa1
13116a4b781bb2
146cc8cc0c42d
153712d3905b1
hex1d2270fd959

2002110110041 has 2 divisors, whose sum is σ = 2002110110042. Its totient is φ = 2002110110040.

The previous prime is 2002110110017. The next prime is 2002110110047. The reversal of 2002110110041 is 1400110112002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1680134440000 + 321975670041 = 1296200^2 + 567429^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002110110041 - 219 = 2002109585753 is a prime.

It is not a weakly prime, because it can be changed into another prime (2002110110047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055055020 + 1001055055021.

It is an arithmetic number, because the mean of its divisors is an integer number (1001055055021).

Almost surely, 22002110110041 is an apocalyptic number.

It is an amenable number.

2002110110041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002110110041 is an equidigital number, since it uses as much as digits as its factorization.

2002110110041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2002110110041 its reverse (1400110112002), we get a palindrome (3402220222043).

The spelling of 2002110110041 in words is "two trillion, two billion, one hundred ten million, one hundred ten thousand, forty-one".