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20021113001 is a prime number
BaseRepresentation
bin10010101001010110…
…011111000010101001
31220200022020220211202
4102221112133002221
5312000401104001
613110401533545
71306066436561
oct225126370251
956608226752
1020021113001
11854443a58a
123a690442b5
131b70b8a836
14d7d01dda1
157c2a3b96b
hex4a959f0a9

20021113001 has 2 divisors, whose sum is σ = 20021113002. Its totient is φ = 20021113000.

The previous prime is 20021112977. The next prime is 20021113037. The reversal of 20021113001 is 10031112002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10961880601 + 9059232400 = 104699^2 + 95180^2 .

It is a cyclic number.

It is not a de Polignac number, because 20021113001 - 222 = 20016918697 is a prime.

It is a super-2 number, since 2×200211130012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20021113051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010556500 + 10010556501.

It is an arithmetic number, because the mean of its divisors is an integer number (10010556501).

Almost surely, 220021113001 is an apocalyptic number.

It is an amenable number.

20021113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021113001 is an equidigital number, since it uses as much as digits as its factorization.

20021113001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 20021113001 its reverse (10031112002), we get a palindrome (30052225003).

Subtracting from 20021113001 its reverse (10031112002), we obtain a palindrome (9990000999).

The spelling of 20021113001 in words is "twenty billion, twenty-one million, one hundred thirteen thousand, one".