Base | Representation |
---|---|
bin | 1001000110101100001110… |
… | …10111000101111101011111 |
3 | 2121212222222211022200211222 |
4 | 10203112013113011331133 |
5 | 10111011220031411133 |
6 | 110325323402403555 |
7 | 4134322600133216 |
oct | 443260727057537 |
9 | 77788884280758 |
10 | 20021113544543 |
11 | 64199a7712601 |
12 | 22b42865005bb |
13 | b22ca15a2367 |
14 | 4d30543aa07d |
15 | 24abdd760e98 |
hex | 1235875c5f5f |
20021113544543 has 4 divisors (see below), whose sum is σ = 20398870403928. Its totient is φ = 19643356685160.
The previous prime is 20021113544507. The next prime is 20021113544567. The reversal of 20021113544543 is 34544531112002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20021113544543 - 28 = 20021113544287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20021113544503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188878429613 + ... + 188878429718.
It is an arithmetic number, because the mean of its divisors is an integer number (5099717600982).
Almost surely, 220021113544543 is an apocalyptic number.
20021113544543 is a deficient number, since it is larger than the sum of its proper divisors (377756859385).
20021113544543 is an equidigital number, since it uses as much as digits as its factorization.
20021113544543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377756859384.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 20021113544543 its reverse (34544531112002), we get a palindrome (54565644656545).
The spelling of 20021113544543 in words is "twenty trillion, twenty-one billion, one hundred thirteen million, five hundred forty-four thousand, five hundred forty-three".
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