Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011010000001001111001 |
3 | 21002101210121222122021021 |
4 | 131020213023100021321 |
5 | 230300311134133423 |
6 | 4131431344542441 |
7 | 264435126250021 |
oct | 35104713201171 |
9 | 7071717878237 |
10 | 2002112021113 |
11 | 70210004a586 |
12 | 284033321a21 |
13 | 116a4bca09c9 |
14 | 6cc8d188a81 |
15 | 3712d61b95d |
hex | 1d2272d0279 |
2002112021113 has 2 divisors, whose sum is σ = 2002112021114. Its totient is φ = 2002112021112.
The previous prime is 2002112021059. The next prime is 2002112021141. The reversal of 2002112021113 is 3111202112002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1585161577024 + 416950444089 = 1259032^2 + 645717^2 .
It is a cyclic number.
It is not a de Polignac number, because 2002112021113 - 217 = 2002111890041 is a prime.
It is not a weakly prime, because it can be changed into another prime (2002113021113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001056010556 + 1001056010557.
It is an arithmetic number, because the mean of its divisors is an integer number (1001056010557).
Almost surely, 22002112021113 is an apocalyptic number.
It is an amenable number.
2002112021113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002112021113 is an equidigital number, since it uses as much as digits as its factorization.
2002112021113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 2002112021113 its reverse (3111202112002), we get a palindrome (5113314133115).
The spelling of 2002112021113 in words is "two trillion, two billion, one hundred twelve million, twenty-one thousand, one hundred thirteen".
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