Base | Representation |
---|---|
bin | 10010101001010110… |
… | …100110011100001111 |
3 | 1220200022022110102100 |
4 | 102221112212130033 |
5 | 312000403041221 |
6 | 13110402330143 |
7 | 1306066624131 |
oct | 225126463417 |
9 | 56608273370 |
10 | 20021143311 |
11 | 8544460334 |
12 | 3a69059953 |
13 | 1b70b9b580 |
14 | d7d02b051 |
15 | 7c2a45926 |
hex | 4a95a670f |
20021143311 has 24 divisors (see below), whose sum is σ = 31215023840. Its totient is φ = 12292606656.
The previous prime is 20021143291. The next prime is 20021143327. The reversal of 20021143311 is 11334112002.
20021143311 is a `hidden beast` number, since 20 + 0 + 211 + 433 + 1 + 1 = 666.
It is not a de Polignac number, because 20021143311 - 223 = 20012754703 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20021143381) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 143536 + ... + 246261.
Almost surely, 220021143311 is an apocalyptic number.
20021143311 is a deficient number, since it is larger than the sum of its proper divisors (11193880529).
20021143311 is a wasteful number, since it uses less digits than its factorization.
20021143311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390255 (or 390252 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 20021143311 its reverse (11334112002), we get a palindrome (31355255313).
The spelling of 20021143311 in words is "twenty billion, twenty-one million, one hundred forty-three thousand, three hundred eleven".
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