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200212000687841 is a prime number
BaseRepresentation
bin101101100001011101111101…
…001011100100011011100001
3222020220002011120022211221212
4231201131331023210123201
5202220233134134002331
61545452042351555505
760112561006401602
oct5541357513443341
9866802146284855
10200212000687841
115888048396598a
121a556515b2bb95
138793bab92397c
143762453861da9
151822e90d6cd2b
hexb6177d2e46e1

200212000687841 has 2 divisors, whose sum is σ = 200212000687842. Its totient is φ = 200212000687840.

The previous prime is 200212000687819. The next prime is 200212000687861. The reversal of 200212000687841 is 148786000212002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 185583976572241 + 14628024115600 = 13622921^2 + 3824660^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200212000687841 is a prime.

It is a super-3 number, since 3×2002120006878413 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (200212000687861) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106000343920 + 100106000343921.

It is an arithmetic number, because the mean of its divisors is an integer number (100106000343921).

Almost surely, 2200212000687841 is an apocalyptic number.

It is an amenable number.

200212000687841 is a deficient number, since it is larger than the sum of its proper divisors (1).

200212000687841 is an equidigital number, since it uses as much as digits as its factorization.

200212000687841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86016, while the sum is 41.

Adding to 200212000687841 its reverse (148786000212002), we get a palindrome (348998000899843).

The spelling of 200212000687841 in words is "two hundred trillion, two hundred twelve billion, six hundred eighty-seven thousand, eight hundred forty-one".