Base | Representation |
---|---|
bin | 101101100001011101111101… |
… | …001101100100011001101011 |
3 | 222020220002011121022110222120 |
4 | 231201131331031210121223 |
5 | 202220233134302241021 |
6 | 1545452042411122323 |
7 | 60112561014014025 |
oct | 5541357515443153 |
9 | 866802147273876 |
10 | 200212001212011 |
11 | 58880484193788 |
12 | 1a5565161433a3 |
13 | 8793baba78429 |
14 | 376245395b015 |
15 | 1822e90e232c6 |
hex | b6177d36466b |
200212001212011 has 24 divisors (see below), whose sum is σ = 293354417753520. Its totient is φ = 121291381381632.
The previous prime is 200212001211979. The next prime is 200212001212099. The reversal of 200212001212011 is 110212100212002.
It is not a de Polignac number, because 200212001212011 - 25 = 200212001211979 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200212001212511) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3981440896 + ... + 3981491181.
It is an arithmetic number, because the mean of its divisors is an integer number (12223100739730).
Almost surely, 2200212001212011 is an apocalyptic number.
200212001212011 is a deficient number, since it is larger than the sum of its proper divisors (93142416541509).
200212001212011 is a wasteful number, since it uses less digits than its factorization.
200212001212011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7962932143 (or 7962932126 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 200212001212011 its reverse (110212100212002), we get a palindrome (310424101424013).
The spelling of 200212001212011 in words is "two hundred trillion, two hundred twelve billion, one million, two hundred twelve thousand, eleven".
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