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20021200414433 is a prime number
BaseRepresentation
bin1001000110101100011001…
…00010011110011011100001
32121220000012212210010221022
410203112030202132123201
510111011404301230213
6110325340144335225
74134325003411211
oct443261442363341
977800185703838
1020021200414433
116419a417561a9
1222b42ab614515
13b22cb659966a
144d3061b40241
1524abe61c0308
hex12358c89e6e1

20021200414433 has 2 divisors, whose sum is σ = 20021200414434. Its totient is φ = 20021200414432.

The previous prime is 20021200414399. The next prime is 20021200414441. The reversal of 20021200414433 is 33441400212002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15357056140864 + 4664144273569 = 3918808^2 + 2159663^2 .

It is a cyclic number.

It is not a de Polignac number, because 20021200414433 - 238 = 19746322507489 is a prime.

It is a super-2 number, since 2×200212004144332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20021200413433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010600207216 + 10010600207217.

It is an arithmetic number, because the mean of its divisors is an integer number (10010600207217).

Almost surely, 220021200414433 is an apocalyptic number.

It is an amenable number.

20021200414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20021200414433 is an equidigital number, since it uses as much as digits as its factorization.

20021200414433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 20021200414433 its reverse (33441400212002), we get a palindrome (53462600626435).

The spelling of 20021200414433 in words is "twenty trillion, twenty-one billion, two hundred million, four hundred fourteen thousand, four hundred thirty-three".