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2002120221111 = 31993334858709
BaseRepresentation
bin11101001000100111101…
…010100010000110110111
321002101211012102020112220
4131020213222202012313
5230300320234033421
64131432240413423
7264435256041513
oct35104752420667
97071735366486
102002120221111
1170210474033a
12284036017273
13116a508b218a
146cc902c1143
153712e1db3c6
hex1d227aa21b7

2002120221111 has 8 divisors (see below), whose sum is σ = 2670833070960. Its totient is φ = 1334077092672.

The previous prime is 2002120221071. The next prime is 2002120221149. The reversal of 2002120221111 is 1111220212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2002120221111 - 213 = 2002120212919 is a prime.

It is a super-4 number, since 4×20021202211114 (a number of 50 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002120221161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167423376 + ... + 167435333.

It is an arithmetic number, because the mean of its divisors is an integer number (333854133870).

Almost surely, 22002120221111 is an apocalyptic number.

2002120221111 is a deficient number, since it is larger than the sum of its proper divisors (668712849849).

2002120221111 is a wasteful number, since it uses less digits than its factorization.

2002120221111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334860705.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 2002120221111 its reverse (1111220212002), we get a palindrome (3113340433113).

The spelling of 2002120221111 in words is "two trillion, two billion, one hundred twenty million, two hundred twenty-one thousand, one hundred eleven".

Divisors: 1 3 1993 5979 334858709 1004576127 667373407037 2002120221111