Search a number
-
+
200212111231500 = 223531989354122291
BaseRepresentation
bin101101100001011110000011…
…110001010000101000001100
3222020220002110021100001100110
4231201132003301100220030
5202220233400433402000
61545452101341200020
760112563521116404
oct5541360361205014
9866802407301313
10200212111231500
11588805302a8a85
121a556546b60010
138793bc87b9614
1437624643d9804
151822e9a906850
hexb61783c50a0c

200212111231500 has 384 divisors, whose sum is σ = 620801454873600. Its totient is φ = 49995221760000.

The previous prime is 200212111231499. The next prime is 200212111231501. The reversal of 200212111231500 is 5132111212002.

It is an interprime number because it is at equal distance from previous prime (200212111231499) and next prime (200212111231501).

It is not an unprimeable number, because it can be changed into a prime (200212111231501) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 8981735355 + ... + 8981757645.

It is an arithmetic number, because the mean of its divisors is an integer number (1616670455400).

Almost surely, 2200212111231500 is an apocalyptic number.

200212111231500 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200212111231500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (310400727436800).

200212111231500 is an abundant number, since it is smaller than the sum of its proper divisors (420589343642100).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200212111231500 is a wasteful number, since it uses less digits than its factorization.

200212111231500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25962 (or 25950 counting only the distinct ones).

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 200212111231500 its reverse (5132111212002), we get a palindrome (205344222443502).

The spelling of 200212111231500 in words is "two hundred trillion, two hundred twelve billion, one hundred eleven million, two hundred thirty-one thousand, five hundred".