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200212221111 = 379533915291
BaseRepresentation
bin1011101001110110010…
…1000000110010110111
3201010210010121122010120
42322131211000302313
511240013312033421
6231550510423023
720315305541310
oct2723545006267
9633703548116
10200212221111
1177a00641051
1232976801a73
1315b59294cb6
149994365607
15531bde48c6
hex2e9d940cb7

200212221111 has 8 divisors (see below), whose sum is σ = 305085289344. Its totient is φ = 114406983480.

The previous prime is 200212221103. The next prime is 200212221113. The reversal of 200212221111 is 111122212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200212221111 - 23 = 200212221103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200212221113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4766957625 + ... + 4766957666.

It is an arithmetic number, because the mean of its divisors is an integer number (38135661168).

Almost surely, 2200212221111 is an apocalyptic number.

200212221111 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

200212221111 is a deficient number, since it is larger than the sum of its proper divisors (104873068233).

200212221111 is an equidigital number, since it uses as much as digits as its factorization.

200212221111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9533915301.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 200212221111 its reverse (111122212002), we get a palindrome (311334433113).

The spelling of 200212221111 in words is "two hundred billion, two hundred twelve million, two hundred twenty-one thousand, one hundred eleven".

Divisors: 1 3 7 21 9533915291 28601745873 66737407037 200212221111