Search a number
-
+
20021223111103 = 47439970349591
BaseRepresentation
bin1001000110101100011011…
…11001000011100110111111
32121220000021110111020220201
410203112031321003212333
510111011431104023403
6110325342315024331
74134325400341234
oct443261571034677
977800243436821
1020021223111103
116419a53548585
1222b42b713b0a7
13b22cbb1b5346
144d3064b6b78b
1524abe81a521d
hex12358de439bf

20021223111103 has 8 divisors (see below), whose sum is σ = 20493783383040. Its totient is φ = 19550603539320.

The previous prime is 20021223111091. The next prime is 20021223111179. The reversal of 20021223111103 is 30111132212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20021223111103 - 29 = 20021223110591 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20021223141103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 485154163 + ... + 485195428.

It is an arithmetic number, because the mean of its divisors is an integer number (2561722922880).

Almost surely, 220021223111103 is an apocalyptic number.

20021223111103 is a deficient number, since it is larger than the sum of its proper divisors (472560271937).

20021223111103 is an equidigital number, since it uses as much as digits as its factorization.

20021223111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 970350077.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 20021223111103 its reverse (30111132212002), we get a palindrome (50132355323105).

The spelling of 20021223111103 in words is "twenty trillion, twenty-one billion, two hundred twenty-three million, one hundred eleven thousand, one hundred three".

Divisors: 1 47 439 20633 970349591 45606430777 425983470449 20021223111103