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200212231131000 = 2332531119293670319
BaseRepresentation
bin101101100001011110001010…
…111010101000111101111000
3222020220002202121221120112200
4231201132022322220331320
5202220234122132143000
61545452121303110200
760112566505211544
oct5541361272507570
9866802677846480
10200212231131000
1158880591a51280
121a55657b142360
138793c175a987a
1437624762caa24
151822ea61dc500
hexb6178aea8f78

200212231131000 has 768 divisors, whose sum is σ = 803888167680000. Its totient is φ = 44396166528000.

The previous prime is 200212231130983. The next prime is 200212231131013. The reversal of 200212231131000 is 131132212002.

200212231131000 is a `hidden beast` number, since 2 + 0 + 0 + 21 + 22 + 311 + 310 + 0 + 0 = 666.

It is a super-3 number, since 3×2002122311310003 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 52713841 + ... + 56384159.

It is an arithmetic number, because the mean of its divisors is an integer number (1046729385000).

Almost surely, 2200212231131000 is an apocalyptic number.

200212231131000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200212231131000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (401944083840000).

200212231131000 is an abundant number, since it is smaller than the sum of its proper divisors (603675936549000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200212231131000 is a wasteful number, since it uses less digits than its factorization.

200212231131000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3670405 (or 3670388 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 200212231131000 its reverse (131132212002), we get a palindrome (200343363343002).

The spelling of 200212231131000 in words is "two hundred trillion, two hundred twelve billion, two hundred thirty-one million, one hundred thirty-one thousand".