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2002130630035 = 53479531210877
BaseRepresentation
bin11101001000101000010…
…010001111010110010011
321002101211221000001220121
4131020220102033112103
5230300330420130120
64131433251451111
7264435443363314
oct35105022172623
97071757001817
102002130630035
1170210a5aa758
122840395b6a97
13116a52ab7bc3
146cc9183060b
15371300955aa
hex1d22848f593

2002130630035 has 16 divisors (see below), whose sum is σ = 2412010853856. Its totient is φ = 1595411469568.

The previous prime is 2002130630009. The next prime is 2002130630057. The reversal of 2002130630035 is 5300360312002.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 2002130630035 - 219 = 2002130105747 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002130629991 and 2002130630009.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1048017 + ... + 2258893.

It is an arithmetic number, because the mean of its divisors is an integer number (150750678366).

Almost surely, 22002130630035 is an apocalyptic number.

2002130630035 is a deficient number, since it is larger than the sum of its proper divisors (409880223821).

2002130630035 is a wasteful number, since it uses less digits than its factorization.

2002130630035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1212182.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 2002130630035 its reverse (5300360312002), we get a palindrome (7302490942037).

The spelling of 2002130630035 in words is "two trillion, two billion, one hundred thirty million, six hundred thirty thousand, thirty-five".

Divisors: 1 5 347 953 1735 4765 330691 1210877 1653455 6054385 420174319 1153965781 2100871595 5769828905 400426126007 2002130630035