Base | Representation |
---|---|
bin | 11101001000101000010… |
… | …010001111010110010011 |
3 | 21002101211221000001220121 |
4 | 131020220102033112103 |
5 | 230300330420130120 |
6 | 4131433251451111 |
7 | 264435443363314 |
oct | 35105022172623 |
9 | 7071757001817 |
10 | 2002130630035 |
11 | 70210a5aa758 |
12 | 2840395b6a97 |
13 | 116a52ab7bc3 |
14 | 6cc9183060b |
15 | 371300955aa |
hex | 1d22848f593 |
2002130630035 has 16 divisors (see below), whose sum is σ = 2412010853856. Its totient is φ = 1595411469568.
The previous prime is 2002130630009. The next prime is 2002130630057. The reversal of 2002130630035 is 5300360312002.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 2002130630035 - 219 = 2002130105747 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2002130629991 and 2002130630009.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1048017 + ... + 2258893.
It is an arithmetic number, because the mean of its divisors is an integer number (150750678366).
Almost surely, 22002130630035 is an apocalyptic number.
2002130630035 is a deficient number, since it is larger than the sum of its proper divisors (409880223821).
2002130630035 is a wasteful number, since it uses less digits than its factorization.
2002130630035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1212182.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 2002130630035 its reverse (5300360312002), we get a palindrome (7302490942037).
The spelling of 2002130630035 in words is "two trillion, two billion, one hundred thirty million, six hundred thirty thousand, thirty-five".
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