200213414220013 has 4 divisors (see below), whose sum is σ = 200213460786240. Its totient is φ = 200213367653788.

The previous prime is 200213414220011. The next prime is 200213414220019. The reversal of 200213414220013 is 310022414312002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200213414220013 - 2¹ = 200213414220011 is a prime.

It is a super-2 number, since 2×200213414220013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200213414220013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200213414220011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16093843 + ... + 25679536.

It is an arithmetic number, because the mean of its divisors is an integer number (50053365196560).

Almost surely, 2^{200213414220013} is an apocalyptic number.

It is an amenable number.

200213414220013 is a deficient number, since it is larger than the sum of its proper divisors (46566227).

200213414220013 is an equidigital number, since it uses as much as digits as its factorization.

200213414220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46566226.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 200213414220013 its reverse (310022414312002), we get a palindrome (510235828532015).

The spelling of 200213414220013 in words is "two hundred trillion, two hundred thirteen billion, four hundred fourteen million, two hundred twenty thousand, thirteen".