Base | Representation |
---|---|
bin | 1011101001110110101… |
… | …1111011001011011001 |
3 | 201010210021000200201202 |
4 | 2322131223323023121 |
5 | 11240014243024423 |
6 | 231551013323545 |
7 | 20315330126153 |
oct | 2723553731331 |
9 | 633707020652 |
10 | 200214033113 |
11 | 77a01669476 |
12 | 329773365b5 |
13 | 15b5977a9a3 |
14 | 99946b7ad3 |
15 | 531c151728 |
hex | 2e9dafb2d9 |
200214033113 has 2 divisors, whose sum is σ = 200214033114. Its totient is φ = 200214033112.
The previous prime is 200214033083. The next prime is 200214033119. The reversal of 200214033113 is 311330412002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109162177609 + 91051855504 = 330397^2 + 301748^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200214033113 is a prime.
It is not a weakly prime, because it can be changed into another prime (200214033119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100107016556 + 100107016557.
It is an arithmetic number, because the mean of its divisors is an integer number (100107016557).
Almost surely, 2200214033113 is an apocalyptic number.
It is an amenable number.
200214033113 is a deficient number, since it is larger than the sum of its proper divisors (1).
200214033113 is an equidigital number, since it uses as much as digits as its factorization.
200214033113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 200214033113 its reverse (311330412002), we get a palindrome (511544445115).
The spelling of 200214033113 in words is "two hundred billion, two hundred fourteen million, thirty-three thousand, one hundred thirteen".
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