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20022012102111 = 36674004034037
BaseRepresentation
bin1001000110101101111001…
…11010110100010111011111
32121220002022110010011002220
410203112330322310113133
510111020040044231421
6110325552501520423
74134354060553455
oct443267472642737
977802273104086
1020022012102111
11641a31894a168
1222b4497413113
13b230b57b2326
144d30db86c9d5
1524ac425a53c6
hex1235bceb45df

20022012102111 has 4 divisors (see below), whose sum is σ = 26696016136152. Its totient is φ = 13348008068072.

The previous prime is 20022012102101. The next prime is 20022012102119. The reversal of 20022012102111 is 11120121022002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20022012102111 - 29 = 20022012101599 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20022012102119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337002017016 + ... + 3337002017021.

It is an arithmetic number, because the mean of its divisors is an integer number (6674004034038).

Almost surely, 220022012102111 is an apocalyptic number.

20022012102111 is a deficient number, since it is larger than the sum of its proper divisors (6674004034041).

20022012102111 is an equidigital number, since it uses as much as digits as its factorization.

20022012102111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6674004034040.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 20022012102111 its reverse (11120121022002), we get a palindrome (31142133124113).

The spelling of 20022012102111 in words is "twenty trillion, twenty-two billion, twelve million, one hundred two thousand, one hundred eleven".

Divisors: 1 3 6674004034037 20022012102111