Base | Representation |
---|---|
bin | 1001000110101101111001… |
… | …11010110100010111011111 |
3 | 2121220002022110010011002220 |
4 | 10203112330322310113133 |
5 | 10111020040044231421 |
6 | 110325552501520423 |
7 | 4134354060553455 |
oct | 443267472642737 |
9 | 77802273104086 |
10 | 20022012102111 |
11 | 641a31894a168 |
12 | 22b4497413113 |
13 | b230b57b2326 |
14 | 4d30db86c9d5 |
15 | 24ac425a53c6 |
hex | 1235bceb45df |
20022012102111 has 4 divisors (see below), whose sum is σ = 26696016136152. Its totient is φ = 13348008068072.
The previous prime is 20022012102101. The next prime is 20022012102119. The reversal of 20022012102111 is 11120121022002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20022012102111 - 29 = 20022012101599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20022012102119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337002017016 + ... + 3337002017021.
It is an arithmetic number, because the mean of its divisors is an integer number (6674004034038).
Almost surely, 220022012102111 is an apocalyptic number.
20022012102111 is a deficient number, since it is larger than the sum of its proper divisors (6674004034041).
20022012102111 is an equidigital number, since it uses as much as digits as its factorization.
20022012102111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6674004034040.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 20022012102111 its reverse (11120121022002), we get a palindrome (31142133124113).
The spelling of 20022012102111 in words is "twenty trillion, twenty-two billion, twelve million, one hundred two thousand, one hundred eleven".
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