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2002211441 is a prime number
BaseRepresentation
bin111011101010111…
…0101001001110001
312011112111212202022
41313111311021301
513100031231231
6530402201225
7100421342066
oct16725651161
95145455668
102002211441
119382180aa
1247a653215
1325ba6cac9
1414dcb2c6d
15bab9cc7b
hex77575271

2002211441 has 2 divisors, whose sum is σ = 2002211442. Its totient is φ = 2002211440.

The previous prime is 2002211401. The next prime is 2002211447. The reversal of 2002211441 is 1441122002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1422798400 + 579413041 = 37720^2 + 24071^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002211441 - 210 = 2002210417 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2002211447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001105720 + 1001105721.

It is an arithmetic number, because the mean of its divisors is an integer number (1001105721).

Almost surely, 22002211441 is an apocalyptic number.

It is an amenable number.

2002211441 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002211441 is an equidigital number, since it uses as much as digits as its factorization.

2002211441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

The square root of 2002211441 is about 44746.0773811515. The cubic root of 2002211441 is about 1260.3852523552.

Adding to 2002211441 its reverse (1441122002), we get a palindrome (3443333443).

The spelling of 2002211441 in words is "two billion, two million, two hundred eleven thousand, four hundred forty-one".