Search a number
-
+
20022212119937 is a prime number
BaseRepresentation
bin1001000110101110010001…
…10101110100110110000001
32121220002211101111002222112
410203113020311310312001
510111020442300314222
6110330024404545105
74134362036644016
oct443271065646601
977802741432875
1020022212119937
11641a410844555
1222b45323b2195
13b23118074781
144d311a25770d
1524ac54e14be2
hex1235c8d74d81

20022212119937 has 2 divisors, whose sum is σ = 20022212119938. Its totient is φ = 20022212119936.

The previous prime is 20022212119933. The next prime is 20022212120041. The reversal of 20022212119937 is 73991121222002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12945287377936 + 7076924742001 = 3597956^2 + 2660249^2 .

It is a cyclic number.

It is not a de Polignac number, because 20022212119937 - 22 = 20022212119933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20022212119894 and 20022212119903.

It is not a weakly prime, because it can be changed into another prime (20022212119933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011106059968 + 10011106059969.

It is an arithmetic number, because the mean of its divisors is an integer number (10011106059969).

Almost surely, 220022212119937 is an apocalyptic number.

It is an amenable number.

20022212119937 is a deficient number, since it is larger than the sum of its proper divisors (1).

20022212119937 is an equidigital number, since it uses as much as digits as its factorization.

20022212119937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The spelling of 20022212119937 in words is "twenty trillion, twenty-two billion, two hundred twelve million, one hundred nineteen thousand, nine hundred thirty-seven".