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20023112112 = 243417148169
BaseRepresentation
bin10010101001011110…
…000111000110110000
31220200110000111002220
4102221132013012300
5312001404041422
613110512441040
71306122434103
oct225136070660
956613014086
1020023112112
118545585543
123a69849180
131b7140a743
14d7d3c073a
157c2cd3e5c
hex4a97871b0

20023112112 has 20 divisors (see below), whose sum is σ = 51726373080. Its totient is φ = 6674370688.

The previous prime is 20023112107. The next prime is 20023112113. The reversal of 20023112112 is 21121132002.

It is a super-2 number, since 2×200231121122 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20023112091 and 20023112100.

It is not an unprimeable number, because it can be changed into a prime (20023112113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208574037 + ... + 208574132.

It is an arithmetic number, because the mean of its divisors is an integer number (2586318654).

Almost surely, 220023112112 is an apocalyptic number.

It is an amenable number.

20023112112 is an abundant number, since it is smaller than the sum of its proper divisors (31703260968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20023112112 is a wasteful number, since it uses less digits than its factorization.

20023112112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 417148180 (or 417148174 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20023112112 its reverse (21121132002), we get a palindrome (41144244114).

The spelling of 20023112112 in words is "twenty billion, twenty-three million, one hundred twelve thousand, one hundred twelve".

Divisors: 1 2 3 4 6 8 12 16 24 48 417148169 834296338 1251444507 1668592676 2502889014 3337185352 5005778028 6674370704 10011556056 20023112112