Base | Representation |
---|---|
bin | 11101001000110011000… |
… | …110100101001101010110 |
3 | 21002102022120111212202111 |
4 | 131020303012211031112 |
5 | 230301213400420342 |
6 | 4131503253501234 |
7 | 264443106141055 |
oct | 35106306451526 |
9 | 7072276455674 |
10 | 2002312123222 |
11 | 7021a2aa2224 |
12 | 28408a34181a |
13 | 116a81592618 |
14 | 6ccab99639c |
15 | 37140e96217 |
hex | 1d2331a5356 |
2002312123222 has 4 divisors (see below), whose sum is σ = 3003468184836. Its totient is φ = 1001156061610.
The previous prime is 2002312123199. The next prime is 2002312123261. The reversal of 2002312123222 is 2223212132002.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×20023121232223 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2002312123193 and 2002312123202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500578030804 + ... + 500578030807.
It is an arithmetic number, because the mean of its divisors is an integer number (750867046209).
Almost surely, 22002312123222 is an apocalyptic number.
2002312123222 is a deficient number, since it is larger than the sum of its proper divisors (1001156061614).
2002312123222 is a wasteful number, since it uses less digits than its factorization.
2002312123222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001156061613.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 2002312123222 its reverse (2223212132002), we get a palindrome (4225524255224).
The spelling of 2002312123222 in words is "two trillion, two billion, three hundred twelve million, one hundred twenty-three thousand, two hundred twenty-two".
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