Base | Representation |
---|---|
bin | 11101001000110011000… |
… | …110111011001000111011 |
3 | 21002102022120200102222111 |
4 | 131020303012323020323 |
5 | 230301213411304201 |
6 | 4131503255433151 |
7 | 264443106664003 |
oct | 35106306731073 |
9 | 7072276612874 |
10 | 2002312213051 |
11 | 7021a3053767 |
12 | 28408a3857b7 |
13 | 116a815c4487 |
14 | 6ccab9bb003 |
15 | 37140eb2b51 |
hex | 1d2331bb23b |
2002312213051 has 2 divisors, whose sum is σ = 2002312213052. Its totient is φ = 2002312213050.
The previous prime is 2002312213021. The next prime is 2002312213117. The reversal of 2002312213051 is 1503122132002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2002312213051 - 229 = 2001775342139 is a prime.
It is a super-3 number, since 3×20023122130513 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2002312213021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001156106525 + 1001156106526.
It is an arithmetic number, because the mean of its divisors is an integer number (1001156106526).
Almost surely, 22002312213051 is an apocalyptic number.
2002312213051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2002312213051 is an equidigital number, since it uses as much as digits as its factorization.
2002312213051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 2002312213051 its reverse (1503122132002), we get a palindrome (3505434345053).
The spelling of 2002312213051 in words is "two trillion, two billion, three hundred twelve million, two hundred thirteen thousand, fifty-one".
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