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20023123120000 = 275471113614099
BaseRepresentation
bin1001000110101111111110…
…01001000000111110000000
32121220012011212200201010121
410203113333021000332000
510111024324004320000
6110330255030510024
74134423441215620
oct443277711007600
977805155621117
1020023123120000
11641a838aaa370
1222b4747505314
13b23231a1cc70
144d31a5238880
1524aca9db5b1a
hex1235ff240f80

20023123120000 has 1280 divisors, whose sum is σ = 68040270144000. Its totient is φ = 5665075200000.

The previous prime is 20023123119949. The next prime is 20023123120001. The reversal of 20023123120000 is 2132132002.

It is a super-3 number, since 3×200231231200003 (a number of 41 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20023123120001) by changing a digit.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 4884877951 + ... + 4884882049.

It is an arithmetic number, because the mean of its divisors is an integer number (53156461050).

Almost surely, 220023123120000 is an apocalyptic number.

20023123120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20023123120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34020135072000).

20023123120000 is an abundant number, since it is smaller than the sum of its proper divisors (48017147024000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20023123120000 is a wasteful number, since it uses less digits than its factorization.

20023123120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4225 (or 4198 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 20023123120000 its reverse (2132132002), we get a palindrome (20025255252002).

The spelling of 20023123120000 in words is "twenty trillion, twenty-three billion, one hundred twenty-three million, one hundred twenty thousand".