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2002313223303 = 3667437741101
BaseRepresentation
bin11101001000110011001…
…010110001110010000111
321002102022122120202210020
4131020303022301302013
5230301214141121203
64131503333230223
7264443121402231
oct35106312616207
97072278522706
102002313223303
117021a3683788
1228408a792373
13116a81889263
146ccabba1251
1537141112153
hex1d2332b1c87

2002313223303 has 4 divisors (see below), whose sum is σ = 2669750964408. Its totient is φ = 1334875482200.

The previous prime is 2002313223301. The next prime is 2002313223319. The reversal of 2002313223303 is 3033223132002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002313223303 - 21 = 2002313223301 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002313223301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333718870548 + ... + 333718870553.

It is an arithmetic number, because the mean of its divisors is an integer number (667437741102).

Almost surely, 22002313223303 is an apocalyptic number.

2002313223303 is a deficient number, since it is larger than the sum of its proper divisors (667437741105).

2002313223303 is an equidigital number, since it uses as much as digits as its factorization.

2002313223303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 667437741104.

The product of its (nonzero) digits is 3888, while the sum is 24.

Adding to 2002313223303 its reverse (3033223132002), we get a palindrome (5035536355305).

The spelling of 2002313223303 in words is "two trillion, two billion, three hundred thirteen million, two hundred twenty-three thousand, three hundred three".

Divisors: 1 3 667437741101 2002313223303