Base | Representation |
---|---|
bin | 1001000110101111111111… |
… | …11000100001100101100011 |
3 | 2121220012012202010110022121 |
4 | 10203113333320201211203 |
5 | 10111024340201334441 |
6 | 110330300153445111 |
7 | 4134423652120006 |
oct | 443277770414543 |
9 | 77805182113277 |
10 | 20023135574371 |
11 | 641a845036536 |
12 | 22b474b710797 |
13 | b23234490a07 |
14 | 4d31a6b5b53d |
15 | 24acab025dd1 |
hex | 1235ffe21963 |
20023135574371 has 2 divisors, whose sum is σ = 20023135574372. Its totient is φ = 20023135574370.
The previous prime is 20023135574357. The next prime is 20023135574423. The reversal of 20023135574371 is 17347553132002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20023135574371 - 25 = 20023135574339 is a prime.
It is not a weakly prime, because it can be changed into another prime (20023135574671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011567787185 + 10011567787186.
It is an arithmetic number, because the mean of its divisors is an integer number (10011567787186).
Almost surely, 220023135574371 is an apocalyptic number.
20023135574371 is a deficient number, since it is larger than the sum of its proper divisors (1).
20023135574371 is an equidigital number, since it uses as much as digits as its factorization.
20023135574371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 20023135574371 in words is "twenty trillion, twenty-three billion, one hundred thirty-five million, five hundred seventy-four thousand, three hundred seventy-one".
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