Base | Representation |
---|---|
bin | 101101100001110001100111… |
… | …101100101110000000100001 |
3 | 222020222002200001211220122001 |
4 | 231201301213230232000201 |
5 | 202221104404432144203 |
6 | 1545505453451244001 |
7 | 60114236153152102 |
oct | 5541614754560041 |
9 | 866862601756561 |
10 | 200233115115553 |
11 | 58889429463a43 |
12 | 1a55a629149601 |
13 | 8795b95161290 |
14 | 3763497b603a9 |
15 | 18237c986e91d |
hex | b61c67b2e021 |
200233115115553 has 32 divisors (see below), whose sum is σ = 238018796531712. Its totient is φ = 166679828352000.
The previous prime is 200233115115529. The next prime is 200233115115563. The reversal of 200233115115553 is 355511511332002.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 200233115115553 - 221 = 200233113018401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200233115115563) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 143995401 + ... + 145379302.
It is an arithmetic number, because the mean of its divisors is an integer number (7438087391616).
Almost surely, 2200233115115553 is an apocalyptic number.
It is an amenable number.
200233115115553 is a deficient number, since it is larger than the sum of its proper divisors (37785681416159).
200233115115553 is a wasteful number, since it uses less digits than its factorization.
200233115115553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289374865.
The product of its (nonzero) digits is 67500, while the sum is 37.
Adding to 200233115115553 its reverse (355511511332002), we get a palindrome (555744626447555).
The spelling of 200233115115553 in words is "two hundred trillion, two hundred thirty-three billion, one hundred fifteen million, one hundred fifteen thousand, five hundred fifty-three".
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