Base | Representation |
---|---|
bin | 100110001100… |
… | …0100001110011 |
3 | 1101200021221211 |
4 | 1030120201303 |
5 | 20111222121 |
6 | 1553100551 |
7 | 332124202 |
oct | 114304163 |
9 | 41607854 |
10 | 20023411 |
11 | 10336981 |
12 | 6857757 |
13 | 41c0c95 |
14 | 2933239 |
15 | 1b57ce1 |
hex | 1318873 |
20023411 has 2 divisors, whose sum is σ = 20023412. Its totient is φ = 20023410.
The previous prime is 20023403. The next prime is 20023417. The reversal of 20023411 is 11432002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20023411 - 23 = 20023403 is a prime.
It is equal to p1272001 and since 20023411 and 1272001 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 20023391 and 20023400.
It is not a weakly prime, because it can be changed into another prime (20023417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011705 + 10011706.
It is an arithmetic number, because the mean of its divisors is an integer number (10011706).
Almost surely, 220023411 is an apocalyptic number.
20023411 is a deficient number, since it is larger than the sum of its proper divisors (1).
20023411 is an equidigital number, since it uses as much as digits as its factorization.
20023411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
The square root of 20023411 is about 4474.7526188606. The cubic root of 20023411 is about 271.5476324126.
Adding to 20023411 its reverse (11432002), we get a palindrome (31455413).
The spelling of 20023411 in words is "twenty million, twenty-three thousand, four hundred eleven".
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