Base | Representation |
---|---|
bin | 1011101001111011110… |
… | …0000110101000011111 |
3 | 201010211201120112121102 |
4 | 2322132330012220133 |
5 | 11240040133122201 |
6 | 231553044023315 |
7 | 20316003566333 |
oct | 2723674065037 |
9 | 633751515542 |
10 | 200235051551 |
11 | 77a12514987 |
12 | 32982391b3b |
13 | 15b60c29832 |
14 | 99973c97c3 |
15 | 531de0426b |
hex | 2e9ef06a1f |
200235051551 has 4 divisors (see below), whose sum is σ = 200318520000. Its totient is φ = 200151583104.
The previous prime is 200235051493. The next prime is 200235051571. The reversal of 200235051551 is 155150532002.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155150532002 = 2 ⋅77575266001.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200235051551 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200235051571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41730626 + ... + 41735423.
It is an arithmetic number, because the mean of its divisors is an integer number (50079630000).
Almost surely, 2200235051551 is an apocalyptic number.
200235051551 is a deficient number, since it is larger than the sum of its proper divisors (83468449).
200235051551 is an equidigital number, since it uses as much as digits as its factorization.
200235051551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83468448.
The product of its (nonzero) digits is 7500, while the sum is 29.
Adding to 200235051551 its reverse (155150532002), we get a palindrome (355385583553).
The spelling of 200235051551 in words is "two hundred billion, two hundred thirty-five million, fifty-one thousand, five hundred fifty-one".
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