Base | Representation |
---|---|
bin | 1001000110110001101010… |
… | …00000000111000101111011 |
3 | 2121220021111212001010221021 |
4 | 10203120311000013011323 |
5 | 10111033201322133301 |
6 | 110330524430523311 |
7 | 4134455023045405 |
oct | 443306500070573 |
9 | 77807455033837 |
10 | 20024026755451 |
11 | 6420162095024 |
12 | 22b495a066537 |
13 | b23346cba2b4 |
14 | 4d324d25db75 |
15 | 24ad0e3ae8a1 |
hex | 12363500717b |
20024026755451 has 2 divisors, whose sum is σ = 20024026755452. Its totient is φ = 20024026755450.
The previous prime is 20024026755431. The next prime is 20024026755503. The reversal of 20024026755451 is 15455762042002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20024026755451 - 29 = 20024026754939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20024026755398 and 20024026755407.
It is not a weakly prime, because it can be changed into another prime (20024026755431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10012013377725 + 10012013377726.
It is an arithmetic number, because the mean of its divisors is an integer number (10012013377726).
Almost surely, 220024026755451 is an apocalyptic number.
20024026755451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20024026755451 is an equidigital number, since it uses as much as digits as its factorization.
20024026755451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672000, while the sum is 43.
Adding to 20024026755451 its reverse (15455762042002), we get a palindrome (35479788797453).
The spelling of 20024026755451 in words is "twenty trillion, twenty-four billion, twenty-six million, seven hundred fifty-five thousand, four hundred fifty-one".
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