Base | Representation |
---|---|
bin | 11101001000111001101… |
… | …011000001100111000011 |
3 | 21002102121020220110210200 |
4 | 131020321223001213003 |
5 | 230301430104340120 |
6 | 4131522232100243 |
7 | 264445615024635 |
oct | 35107153014703 |
9 | 7072536813720 |
10 | 2002422340035 |
11 | 70224a2317a7 |
12 | 2840bb234683 |
13 | 116a9b372580 |
14 | 6ccbc486a55 |
15 | 3714a9b7e90 |
hex | 1d239ac19c3 |
2002422340035 has 24 divisors (see below), whose sum is σ = 3737855035824. Its totient is φ = 985807920960.
The previous prime is 2002422340007. The next prime is 2002422340049. The reversal of 2002422340035 is 5300432242002.
It is a happy number.
2002422340035 is a `hidden beast` number, since 2 + 0 + 0 + 2 + 4 + 223 + 400 + 35 = 666.
It is not a de Polignac number, because 2002422340035 - 215 = 2002422307267 is a prime.
It is a super-3 number, since 3×20024223400353 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2002422339990 and 2002422340008.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1711471501 + ... + 1711472670.
It is an arithmetic number, because the mean of its divisors is an integer number (155743959826).
Almost surely, 22002422340035 is an apocalyptic number.
2002422340035 is a deficient number, since it is larger than the sum of its proper divisors (1735432695789).
2002422340035 is a wasteful number, since it uses less digits than its factorization.
2002422340035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3422944195 (or 3422944192 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 27.
Adding to 2002422340035 its reverse (5300432242002), we get a palindrome (7302854582037).
The spelling of 2002422340035 in words is "two trillion, two billion, four hundred twenty-two million, three hundred forty thousand, thirty-five".
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